Integrand size = 29, antiderivative size = 135 \[ \int \frac {\sec (c+d x) (A+B \sin (c+d x))}{(a+b \sin (c+d x))^2} \, dx=-\frac {(A+B) \log (1-\sin (c+d x))}{2 (a+b)^2 d}+\frac {(A-B) \log (1+\sin (c+d x))}{2 (a-b)^2 d}-\frac {\left (2 a A b-a^2 B-b^2 B\right ) \log (a+b \sin (c+d x))}{\left (a^2-b^2\right )^2 d}+\frac {A b-a B}{\left (a^2-b^2\right ) d (a+b \sin (c+d x))} \]
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Time = 0.15 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.069, Rules used = {2916, 815} \[ \int \frac {\sec (c+d x) (A+B \sin (c+d x))}{(a+b \sin (c+d x))^2} \, dx=\frac {A b-a B}{d \left (a^2-b^2\right ) (a+b \sin (c+d x))}-\frac {\left (a^2 (-B)+2 a A b-b^2 B\right ) \log (a+b \sin (c+d x))}{d \left (a^2-b^2\right )^2}-\frac {(A+B) \log (1-\sin (c+d x))}{2 d (a+b)^2}+\frac {(A-B) \log (\sin (c+d x)+1)}{2 d (a-b)^2} \]
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Rule 815
Rule 2916
Rubi steps \begin{align*} \text {integral}& = \frac {b \text {Subst}\left (\int \frac {A+\frac {B x}{b}}{(a+x)^2 \left (b^2-x^2\right )} \, dx,x,b \sin (c+d x)\right )}{d} \\ & = \frac {b \text {Subst}\left (\int \left (\frac {A+B}{2 b (a+b)^2 (b-x)}+\frac {-A b+a B}{(a-b) b (a+b) (a+x)^2}+\frac {-2 a A b+a^2 B+b^2 B}{(a-b)^2 b (a+b)^2 (a+x)}+\frac {A-B}{2 (a-b)^2 b (b+x)}\right ) \, dx,x,b \sin (c+d x)\right )}{d} \\ & = -\frac {(A+B) \log (1-\sin (c+d x))}{2 (a+b)^2 d}+\frac {(A-B) \log (1+\sin (c+d x))}{2 (a-b)^2 d}-\frac {\left (2 a A b-a^2 B-b^2 B\right ) \log (a+b \sin (c+d x))}{\left (a^2-b^2\right )^2 d}+\frac {A b-a B}{\left (a^2-b^2\right ) d (a+b \sin (c+d x))} \\ \end{align*}
Time = 0.88 (sec) , antiderivative size = 178, normalized size of antiderivative = 1.32 \[ \int \frac {\sec (c+d x) (A+B \sin (c+d x))}{(a+b \sin (c+d x))^2} \, dx=\frac {-\frac {B ((-a+b) \log (1-\sin (c+d x))+(a+b) \log (1+\sin (c+d x))-2 b \log (a+b \sin (c+d x)))}{2 b (-a+b) (a+b)}+b \left (A-\frac {a B}{b}\right ) \left (-\frac {\log (1-\sin (c+d x))}{2 b (a+b)^2}+\frac {\log (1+\sin (c+d x))}{2 (a-b)^2 b}-\frac {2 a \log (a+b \sin (c+d x))}{(a-b)^2 (a+b)^2}+\frac {1}{\left (a^2-b^2\right ) (a+b \sin (c+d x))}\right )}{d} \]
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Time = 1.02 (sec) , antiderivative size = 128, normalized size of antiderivative = 0.95
method | result | size |
derivativedivides | \(\frac {\frac {\left (A -B \right ) \ln \left (1+\sin \left (d x +c \right )\right )}{2 \left (a -b \right )^{2}}+\frac {\left (-A -B \right ) \ln \left (\sin \left (d x +c \right )-1\right )}{2 \left (a +b \right )^{2}}+\frac {A b -B a}{\left (a +b \right ) \left (a -b \right ) \left (a +b \sin \left (d x +c \right )\right )}-\frac {\left (2 A a b -B \,a^{2}-B \,b^{2}\right ) \ln \left (a +b \sin \left (d x +c \right )\right )}{\left (a +b \right )^{2} \left (a -b \right )^{2}}}{d}\) | \(128\) |
default | \(\frac {\frac {\left (A -B \right ) \ln \left (1+\sin \left (d x +c \right )\right )}{2 \left (a -b \right )^{2}}+\frac {\left (-A -B \right ) \ln \left (\sin \left (d x +c \right )-1\right )}{2 \left (a +b \right )^{2}}+\frac {A b -B a}{\left (a +b \right ) \left (a -b \right ) \left (a +b \sin \left (d x +c \right )\right )}-\frac {\left (2 A a b -B \,a^{2}-B \,b^{2}\right ) \ln \left (a +b \sin \left (d x +c \right )\right )}{\left (a +b \right )^{2} \left (a -b \right )^{2}}}{d}\) | \(128\) |
parallelrisch | \(\frac {-2 \left (a +b \sin \left (d x +c \right )\right ) \left (A a b -\frac {1}{2} B \,a^{2}-\frac {1}{2} B \,b^{2}\right ) a \ln \left (2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )-a \left (a -b \right )^{2} \left (a +b \sin \left (d x +c \right )\right ) \left (A +B \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+\left (a \left (a +b \right ) \left (a +b \sin \left (d x +c \right )\right ) \left (A -B \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )-b \sin \left (d x +c \right ) \left (a -b \right ) \left (A b -B a \right )\right ) \left (a +b \right )}{\left (a -b \right )^{2} \left (a +b \right )^{2} a d \left (a +b \sin \left (d x +c \right )\right )}\) | \(184\) |
norman | \(\frac {-\frac {2 b \left (A b -B a \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d a \left (a^{2}-b^{2}\right )}-\frac {2 b \left (A b -B a \right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a \left (a^{2}-b^{2}\right )}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \left (\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \right )}+\frac {\left (A -B \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{d \left (a^{2}-2 a b +b^{2}\right )}-\frac {\left (A +B \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{\left (a^{2}+2 a b +b^{2}\right ) d}-\frac {\left (2 A a b -B \,a^{2}-B \,b^{2}\right ) \ln \left (\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \right )}{d \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )}\) | \(259\) |
risch | \(-\frac {2 i B \,a^{2} c}{d \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )}-\frac {2 i B \,a^{2} x}{a^{4}-2 a^{2} b^{2}+b^{4}}-\frac {2 i \left (A b -B a \right ) {\mathrm e}^{i \left (d x +c \right )}}{d \left (-a^{2}+b^{2}\right ) \left (b \,{\mathrm e}^{2 i \left (d x +c \right )}-b +2 i a \,{\mathrm e}^{i \left (d x +c \right )}\right )}+\frac {i B c}{\left (a^{2}+2 a b +b^{2}\right ) d}+\frac {4 i A a b x}{a^{4}-2 a^{2} b^{2}+b^{4}}+\frac {i B x}{a^{2}+2 a b +b^{2}}-\frac {i A c}{d \left (a^{2}-2 a b +b^{2}\right )}-\frac {i A x}{a^{2}-2 a b +b^{2}}+\frac {i A x}{a^{2}+2 a b +b^{2}}-\frac {2 i B \,b^{2} c}{d \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )}+\frac {i A c}{\left (a^{2}+2 a b +b^{2}\right ) d}+\frac {4 i A a b c}{d \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )}-\frac {2 i B \,b^{2} x}{a^{4}-2 a^{2} b^{2}+b^{4}}+\frac {i B x}{a^{2}-2 a b +b^{2}}+\frac {i B c}{d \left (a^{2}-2 a b +b^{2}\right )}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) A}{\left (a^{2}+2 a b +b^{2}\right ) d}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) B}{\left (a^{2}+2 a b +b^{2}\right ) d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) A}{d \left (a^{2}-2 a b +b^{2}\right )}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) B}{d \left (a^{2}-2 a b +b^{2}\right )}-\frac {2 \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1+\frac {2 i a \,{\mathrm e}^{i \left (d x +c \right )}}{b}\right ) A a b}{d \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )}+\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1+\frac {2 i a \,{\mathrm e}^{i \left (d x +c \right )}}{b}\right ) B \,a^{2}}{d \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )}+\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1+\frac {2 i a \,{\mathrm e}^{i \left (d x +c \right )}}{b}\right ) B \,b^{2}}{d \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )}\) | \(665\) |
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Leaf count of result is larger than twice the leaf count of optimal. 283 vs. \(2 (129) = 258\).
Time = 0.40 (sec) , antiderivative size = 283, normalized size of antiderivative = 2.10 \[ \int \frac {\sec (c+d x) (A+B \sin (c+d x))}{(a+b \sin (c+d x))^2} \, dx=-\frac {2 \, B a^{3} - 2 \, A a^{2} b - 2 \, B a b^{2} + 2 \, A b^{3} - 2 \, {\left (B a^{3} - 2 \, A a^{2} b + B a b^{2} + {\left (B a^{2} b - 2 \, A a b^{2} + B b^{3}\right )} \sin \left (d x + c\right )\right )} \log \left (b \sin \left (d x + c\right ) + a\right ) - {\left ({\left (A - B\right )} a^{3} + 2 \, {\left (A - B\right )} a^{2} b + {\left (A - B\right )} a b^{2} + {\left ({\left (A - B\right )} a^{2} b + 2 \, {\left (A - B\right )} a b^{2} + {\left (A - B\right )} b^{3}\right )} \sin \left (d x + c\right )\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + {\left ({\left (A + B\right )} a^{3} - 2 \, {\left (A + B\right )} a^{2} b + {\left (A + B\right )} a b^{2} + {\left ({\left (A + B\right )} a^{2} b - 2 \, {\left (A + B\right )} a b^{2} + {\left (A + B\right )} b^{3}\right )} \sin \left (d x + c\right )\right )} \log \left (-\sin \left (d x + c\right ) + 1\right )}{2 \, {\left ({\left (a^{4} b - 2 \, a^{2} b^{3} + b^{5}\right )} d \sin \left (d x + c\right ) + {\left (a^{5} - 2 \, a^{3} b^{2} + a b^{4}\right )} d\right )}} \]
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\[ \int \frac {\sec (c+d x) (A+B \sin (c+d x))}{(a+b \sin (c+d x))^2} \, dx=\int \frac {\left (A + B \sin {\left (c + d x \right )}\right ) \sec {\left (c + d x \right )}}{\left (a + b \sin {\left (c + d x \right )}\right )^{2}}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 147, normalized size of antiderivative = 1.09 \[ \int \frac {\sec (c+d x) (A+B \sin (c+d x))}{(a+b \sin (c+d x))^2} \, dx=\frac {\frac {2 \, {\left (B a^{2} - 2 \, A a b + B b^{2}\right )} \log \left (b \sin \left (d x + c\right ) + a\right )}{a^{4} - 2 \, a^{2} b^{2} + b^{4}} + \frac {{\left (A - B\right )} \log \left (\sin \left (d x + c\right ) + 1\right )}{a^{2} - 2 \, a b + b^{2}} - \frac {{\left (A + B\right )} \log \left (\sin \left (d x + c\right ) - 1\right )}{a^{2} + 2 \, a b + b^{2}} - \frac {2 \, {\left (B a - A b\right )}}{a^{3} - a b^{2} + {\left (a^{2} b - b^{3}\right )} \sin \left (d x + c\right )}}{2 \, d} \]
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Time = 0.35 (sec) , antiderivative size = 205, normalized size of antiderivative = 1.52 \[ \int \frac {\sec (c+d x) (A+B \sin (c+d x))}{(a+b \sin (c+d x))^2} \, dx=\frac {\frac {2 \, {\left (B a^{2} b - 2 \, A a b^{2} + B b^{3}\right )} \log \left ({\left | b \sin \left (d x + c\right ) + a \right |}\right )}{a^{4} b - 2 \, a^{2} b^{3} + b^{5}} - \frac {{\left (A + B\right )} \log \left ({\left | -\sin \left (d x + c\right ) + 1 \right |}\right )}{a^{2} + 2 \, a b + b^{2}} + \frac {{\left (A - B\right )} \log \left ({\left | -\sin \left (d x + c\right ) - 1 \right |}\right )}{a^{2} - 2 \, a b + b^{2}} - \frac {2 \, {\left (B a^{2} b \sin \left (d x + c\right ) - 2 \, A a b^{2} \sin \left (d x + c\right ) + B b^{3} \sin \left (d x + c\right ) + 2 \, B a^{3} - 3 \, A a^{2} b + A b^{3}\right )}}{{\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} {\left (b \sin \left (d x + c\right ) + a\right )}}}{2 \, d} \]
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Time = 0.45 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.97 \[ \int \frac {\sec (c+d x) (A+B \sin (c+d x))}{(a+b \sin (c+d x))^2} \, dx=\frac {A\,b-B\,a}{d\,\left (a^2-b^2\right )\,\left (a+b\,\sin \left (c+d\,x\right )\right )}-\frac {\ln \left (\sin \left (c+d\,x\right )-1\right )\,\left (\frac {A}{2}+\frac {B}{2}\right )}{d\,{\left (a+b\right )}^2}+\frac {\ln \left (a+b\,\sin \left (c+d\,x\right )\right )\,\left (B\,a^2-2\,A\,a\,b+B\,b^2\right )}{d\,{\left (a^2-b^2\right )}^2}+\frac {\ln \left (\sin \left (c+d\,x\right )+1\right )\,\left (\frac {A}{2}-\frac {B}{2}\right )}{d\,{\left (a-b\right )}^2} \]
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